$y^4-9y^2x^2=16y$
$4-8+12\cdot24-32$
$x ^ { \frac { x } { x } }$
$2\sin^2\left(x\right)=-3\cos\left(x\right)$
$13 x ^ { 5 } ( 7 x ^ { 2 } y ^ { 3 } )$
$\left(y=8x+3\right)-\left(y=4x-1\right)$
$\cos x\left(\sec x-1\right)=\sin^2x$
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