$\frac{4}{x}\cdot\frac{3}{5}$
$\sqrt{a^3}\cdot\sqrt{b^4}+\sqrt{a^2}\cdot\sqrt{b^2}$
$-2y+24$
$-80+-50$
$\lim_{x\to\:0}\:\frac{\left(6\sin\left(x\right)cos\left(x\right)-x\right)}{tan\left(x\right)-x}$
$\left(-2x^4y\right)\left(3xy^2\right)$
$\frac{3}{4}\left(3x-5\right)\:$
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