$-x^4+2x^3-3x+\frac{1}{x+1}$
$\sin\left(x\right)\cdot\left(\sec\left(x\right)+\tan\left(x\right)\right)$
$1a^{10}-2a^5+1$
$x'=\frac{-100t}{\left(x-10\right)}$
$2x^2+10x+7=0$
$u'=-3u-1+x^2$
$-9\cdot\left(-3\right)\cdot14$
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