$\frac{\left(-6x^4+4x^3+3x^2+9x+9\right)}{\left(-4+x\right)}$
$4x^2+3y^2+6y=9$
$\left(y+5\right)^2-\left(2y+1\right)^2$
$\frac{d}{dx}\left(x^{6\tan\left(x\right)}\right)$
$-9\left(x-3\right)$
$\left(6-x\right)\left(x-2\right)$
$\left(-9+4i\right)\left(9+i\right)$
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