$\frac{d}{dx}arc\:cos\:x^2$
$2x^2-6x-8$
$64m^2-32m-4$
$3y-2x-3-5$
$\int\frac{x^3}{\sqrt{\left(4x^2+9\right)}}dx$
$\int_{-1}^3x^3+2dx$
$\frac{cos3x-cos7x}{2sin5x}=sin2x$
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