$4x-4+4x-4$
$\frac{x^4-x^3+x^2-3x-6}{x-1}$
$cos^2x-cos^2x\cdot\:\:sin^2x$
$\int27t^3-1dx$
$\left(\frac{1}{3}a^2b\right)\left(\frac{2}{3}ab^3c\right)\left(\frac{5}{4}ac^2\right)\left(\frac{7}{2}b^2c^3\right)$
$2x^2+5x=2$
$\left(3y^3\right)^4$
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