$10-\left(15-1\right)$
$\frac{\sin^2\left(b\right)}{1+\cos\left(b\right)}=1-\cos\left(b\right)$
$\left(12+9mn\right)\left(12-9mn\right)$
$-2\left(7x+4\right)$
$\left(2x^2+4y\right)^2$
$-x<6$
$\lim_{x\to3}\left(\frac{2x-\sqrt{48-4x}}{2x^2+x-15}\right)$
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