$-4=\frac{3x-14}{2}$

$\int _ { 1 } ^ { x ^ { 2 } } t d t$

$\left(6d-15\:\right)\left(6d+8\right)-\left(12d-3\right)^2+5\left(3d-10\right)$

$\left(\frac{7x}{5}+\frac{9}{2}\right)^2$

$\int\left(\left(\cos\left(x\right)+1\right)^3\left(\cos\left(x\right)-4\right)\sin\left(x\right)\right)dx$

$4\sin^2x+4cosx-5=0$

$\left(2x+\frac{3}{x}\right)^2$