$\int\left(3x+5\right)\ln\left(x\right)dx$
$\left(2x-y\right)dx+\left(x+6y\right)dy=0$
$\left(\frac{x^2y}{xy^6}\right)^6$
$\int_{01}^{\infty}\left(\frac{1}{x^2}\right)dx$
$\frac{120}{-60}$
$-500q+60q^2$
$-6x^2+5x-50$
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