$\left(2x+3\right)dx+\left(2y-2\right)dy=0$
$1+\sin\left(x\right)=\frac{1}{1-\sin\left(x\right)}$
$dy=\left(y-y^{2}\right)dx$
$\left(\sqrt{3x}+2\right)\left(\sqrt{3x}-4\right)$
$\frac{dy}{dx}=\frac{y^4+x^4}{4y^3x}$
$200+75+50+150+20+35$
$6-2y=-8$
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