$\frac{dy}{dx}=\frac{\sqrt{1+x^2}}{x\cdot y^2}$
$\lim_{x\to\infty}\:x\:ln\left(\frac{\left(x+a\right)}{\left(x-a\right)}\right)$
$2x+3y-\left(4+2\left(3-x\right)-2x+y\right)$
$t^2\frac{dy}{dt}+3ty=\sqrt{1+t^2}$
$-2\cos2x=2\sin x$
$4\csc x+9=0$
$x-1>4$
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