$\int\frac{y}{1-y^4}dy$
$\frac{1}{\sqrt{x}}=\frac{d^2x}{dz^2}$
$4x>10$
$4x^2+32x+64=0$
$\frac{dy}{dx}=\ln\left(x+\sin x\right)$
$4xyz^4\left(-6x^4y^3z^2+2xy^5\right)$
$\int\frac{5x-3}{x^2+4}dx$
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