$\lim_{x\to\infty}\left(\frac{\left(2x-1\right)^{x-2}}{\left(2x+3\right)^{x-2}}\right)$
$-1+\frac{3}{-1}+\frac{2}{-1}$
$\frac{8x^2+6x+4}{x+2}$
$\frac{9+a}{a\left(1-\left(1+b\right)\right)+2+ab}$
$\left(-7z+4\right)-\left(-8z+4\right)$
$x^2-2x+37$
$\frac{2}{x-1}-\frac{3}{x}=2$
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