$2x^2y^3+3y^2$
$\frac{x^2+3x}{x-1}$
$-2x-7=5$
$5x^2+4x-1=0$
$\left(2y+3x^2\right).\left(4y+3x^2\right)$
$\left(40\:x^2y^2z-6xy^3\right)$
$2\left(1\right)^3-10\left(1\right)^2+2\left(1\right)-10$
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