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Exercise

−2t+2+5t+2=−7+3t+2-\frac{2}{t+2}+\frac{5}{t+2}=-7+\frac{3}{t+2}

Step-by-step Solution

1

Combine fractions with common denominator t+2t+2

3t+2=−7+3t+2\frac{3}{t+2}=-7+\frac{3}{t+2}
2

Move everything to the left hand side of the equation

3t+2+7+−3t+2=0\frac{3}{t+2}+7+\frac{-3}{t+2}=0
3

Combine fractions with common denominator t+2t+2

0t+2+7=0\frac{0}{t+2}+7=0
4

Zero divided by anything is equal to zero

7=07=0
5

77 is not equal to 00

false

Final answer to the exercise

false

Try other ways to solve this exercise

  • Choose an option
  • Solve for t
  • Find the derivative using the definition
  • Solve by quadratic formula (general formula)
  • Simplify
  • Find the integral
  • Find the derivative
  • Factor
  • Factor by completing the square
  • Find the roots
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Similar Questions Solved

4x+2=6x−2\frac{4}{x+2}=\frac{6}{x-2}

3x+1−12=13x+3\frac{3}{x+1}-\frac{1}{2}=\frac{1}{3x+3}

2x+45x=2x\frac{2x+4}{5x}=\frac{2}{x}

5x−7=2x−2\frac{5}{x-7}=\frac{2}{x-2}

2x+33x=x2x−3\frac{2x+3}{3x}=\frac{x}{2x-3}

x+1x−2=x−3x\frac{x+1}{x-2}=\frac{x-3}{x}

x2=8x\frac{x}{2}=\frac{8}{x}

Main Topic: Equations

In mathematics, an equation is a statement of an equality containing one or more variables. Solving the equation consists of determining which values of the variables make the equality true. In this situation, variables are also known as unknowns and the values which satisfy the equality are known as solutions.

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−2t+2 +5t+2 =−7+3t+2 
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