$\left(\frac{1}{4}+\left(-4ab^2\right)\right)^2$
$f\left(x\right)=5.\left(x+1\right)\left(x^2+x-2\right)$
$12x+3y=6$
$-4x^2+2x-4$
$5\left(a^2\right)^4$
$\frac{4x^3+0x^2+x-12}{2x-3}$
$2^{\infty}$
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