$\tan^2x+2\sec^2x$
$-243^{\frac{1}{5}}$
$3x^2-x^2+5x-7x+1-3$
$\frac{dy}{dx}=\frac{x}{e^x}$
$\left(4\:x\:+\:10\:y\right)^4$
$\left(4+\left(-2\right)\right)-\left(4+5\right)$
$x\:\frac{dy}{dx}=\left(1-2y\right)$
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