$x^2+4x-5\ge0$
$-\frac{5}{6}x^2y-\frac{3}{8}x^2y$
$5x^3-4x^3-\frac{1}{5}x^3$
$\left(\frac{3}{4}x-\frac{1}{2}\right)^2$
$14\:-\:\left(8\:+\:7\right)\:-\:\left[4\:+\:2\:-3\:-\:\left(-4\:+5\right)\:\right]$
$\frac{6x^4+5x^3-1}{2x^2+x-1}$
$\frac{-3x-2}{x^2+13x+36}$
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