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Solving: tan⁡(n)+cot⁡(n)=sec⁡(n)cos⁡(n)\tan\left(n\right)+\cot\left(n\right)=\frac{\sec\left(n\right)}{\cos\left(n\right)}
Solve instead: tan⁡(a)+cot⁡(n)=sec⁡(n)cos⁡(n)\tan\left(a\right)+\cot\left(n\right)=\frac{\sec\left(n\right)}{\cos\left(n\right)}

Exercise

tan⁡(a)+cot⁡(n)=sec⁡(n)cos⁡(n)\tan\left(a\right)+\cot\left(n\right)=\frac{\sec\left(n\right)}{\cos\left(n\right)}

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Final answer to the exercise

n=14π+πn, n=54π+πn ,  n∈Zn=\frac{1}{4}\pi+\pi n,\:n=\frac{5}{4}\pi+\pi n\:,\:\:n\in\Z

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tan(a)+cot(n)=sec(n)cos(n) 
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