$-27\:=\:3s\:-\:3$
$\int\:\frac{4e^{3x}}{1+e^{2x}}dx$
$\int r\cos\left(\theta\right)dr$
$6x-2y=0$
$\frac{54a^4b^3c}{63a^2b^5c^2}$
$-2\int\left(\frac{u}{\left(u-1\right)\left(2u-1\right)}\right)du$
$\left(a\:-\:2\right)\:\left(a\:-\:4\right)$
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