$y2-4y+3$
$\frac{4}{x-1}=\frac{x+1}{12}$
$-8=3+v$
$\left(10x^2-15y^3\right)^3$
$\left(-3mn^2\right)\left(-2mn^3\right)\left(m^5\right)$
$b^2+19b+84$
$\left(2x-1\right)^2\cdot\left(1+3x\right)^2$
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