$\frac{2x^3}{2x^2-4x+3}$
$\int\left(\frac{\left(x+3\right)}{\sqrt{16-x^2}}\right)dx$
$\int_0^c\left(x\cdot\:\sin\:\left(a\left(b-x\right)\right)\right)dx$
$\lim_{x\to4\:}x^2-2x$
$-3x^3+5x^2-4x+1-3+5x-4x^2-x^3$
$-2+5x^3+3y^2+4x^3-7+3-5x^3$
$\left(xy^2+3xy\right)dx-dy=0$
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