$4^3x\:\left(4^2\right)^5x\:4^6$
$x^2-x>1$
$\left(y-9\right)\cdot\left(y+3\right)$
$-6n+n+3u$
$x^2+12x+35=0$
$\frac{1}{3}x^5-2x^4-\frac{2}{5}x-0,3x^5-1,6x+2x^4$
$\int\frac{1}{3\left(x+1\right)^2}dx$
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