$\left(8y-\frac{1}{4}\right)^2$
$\frac{10x^2+7x-12}{2x+3}$
$\int10x^2\cdot\cos\left(x\right)dx$
$5a-\sqrt{3b}$
$sec3x=2$
$\sqrt{2}cos3x=-1$
$\sqrt{2}x\sqrt{6}$
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