$5y^7\cdot4y^6$
$-5-4+8+6q+8q-1+5q+3+9q$
$6bc-9c^2-12cd-8bf-12cf+16df$
$12-6x>24$
$\frac{dy}{dx}=\frac{x^2}{6y^2}$
$\frac{x^4-2x^2+2x-35}{x+3}$
$5\:2\:3-3\:3\:2$
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