$\ln\left(x\right)\left(x^2-2x+3\right)-\int\left(\frac{x^3}{3}-x^2+3x\right)\frac{1}{x}dx$

$\sin\left(b\right)\tan\left(b\right)=\frac{1-\cos^2\left(b\right)}{\cos\left(b\right)}$

$\frac{x^3+5x^2+10x-15}{x-4}$

$\frac{9x^2+12x+4}{3x+2}$

$\sqrt[4]{11^5}.7^7$

$\left(6x^4+5x+9\right)^3$

$\int\frac{6}{\left(x+4\right)\left(x-2\right)}dx$