∫w2−4w+1w−3dw\int\frac{w^2-4w+1}{w-3}dw∫w−3w2−4w+1dw
(ma+h)2\left(ma+h\right)^2(ma+h)2
v(t)=6t−t2v\left(t\right)=6t-t^2v(t)=6t−t2
∫sin(4x)⋅cos(6x)dx\int\sin\left(4x\right)\cdot\cos\left(6x\right)dx∫sin(4x)⋅cos(6x)dx
−∫1u−1du-\int\frac{1}{u-1}du−∫u−11du
9(p+5)9\left(p+5\right)9(p+5)
∫−11(x3x−1)dx\int_{-1}^1\left(x^3\sqrt{x-1}\right)dx∫−11(x3x−1)dx
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