$\int\left(t\left(3t-2\right)^{\frac{1}{6}}\right)dt$

$\left(4y-3x^3\right)^2$

$a^2x^2-b^2y^2-ax-by$

$2^4\cdot3$

$\left[\left(2^3+2^5\right)-\left(-3\right)^5\right]\cdot\left(-8\right)^2+5^2$

$1+\sqrt{3}+1-\sqrt{3}$

$\lim_{x\to0}\left(\frac{sen\left(4x\right)}{x}\right)$