$\int\left(\left(3+x\right)\sqrt{1+2x}\right)dx$

$100m^2-169y^2$

$\int_{-\infty}^0\left(\frac{4}{16+x^2}\right)dx$

$\left(mn-12\right)\left(mn+7\right)$

$\left(x+\left(y^{2\:}-xy\right)^{\frac{1}{2}}\right)\frac{dy}{dx}$

$5\left(2\right)^2-2\left(5-3\right)-3-1$

$\left(2x^2y-4m\right)^2$