$\frac{dy^2}{dx}=\frac{5x^2}{4y}$

$\sin2x=2\sin^2x$

$\frac{secx}{tanx-sinx}=\frac{1+cosx}{sin^3x}$

$\int1.6e^{\left(0.4x+3\right)}dx$

$t\frac{dy}{dt}=\frac{\left(t+1\right)^2}{y}$

$\left(1+\frac{\tan\:\left(x\right)}{\cot\:\left(x\right)}\right)\left(\cos\left(x\right)^2\right)$

$\frac{5}{3}-x>3$