$\left(12+\sqrt{6^2-4\cdot5}\right)$
$\lim_{x\to\infty}\left(\frac{-2x^3+4x^5}{x^3+4x^5}\right)$
$\left(2^{-10}\cdot4^2\right)^7$
$\left(2z+6x\right)$
$\frac{dx}{dt}\left(\frac{1}{t}-1\right)x=4e^t$
$x^2+11x-5=0$
$-3\left(-5+7\right)$
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