$\left(x+y\right)\left(4a+4x\right)$

$tan^{-1}=\frac{101}{148}$

$x^2y^2-2x=3$

$125x^3+27y^6$

$g\left(x\right)=\left(\frac{1}{x^2-x}\right)$

$\left(1+tan\left(b\right)\right)^2+\left(1-tan\left(b\right)\right)^2=2sec^2\left(b\right)$

$sen\left(2x-50^{\circ}\right).csc\left(x+20^{\circ}\right)=1$