$2x+12=5x-12$
$-3\le10x-8$
$4.1\:10^6\:-\:7.2\:10^2$
$-4\:x\:-8\:x\:-1$
$4x^2-x+4\:\cdot\:2x^2+x-3$
$\left(3x\right)\left(-24xy\right)$
$\frac{d}{dx}2x^3+3xy+y^2=0$
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