$\frac{x-3}{x^2-9}=\frac{x+6}{x+3}$
$\left(x-\sqrt{2}\right)\left(x^2+x\sqrt{2}+2\right)$
$9x^2-18xy+9y^2$
$4x^2-16x-36$
$x^2-4x+7>0$
$\log_x\left(4\right)+\log_x\left(2\right)=1$
$2a^2b+7bxy5$
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