$\left(4y^5\right)^2$
$\int2^{-x}\:dx$
$\frac{d}{dx}\left(\sqrt{x^3+2}\right)$
$\frac{16}{-1}$
$15\cdot m^2\cdot\left(\frac{1}{m}\right)^4$
$-5x\:-\:\left(-14\right)\:=\:\left(-21\right)$
$3x+6\ge2x+12.xeq$
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