$\int_0^3\frac{1}{\sqrt{9-x^2}}dx$
$\int\left(-8\sin\left(2x\right)\right)dx$
$\left(7x+y^{2}\right)^{3}$
$\left(x^3-y^3\right)^2$
$4+y=9.5$
$-8x^2-2x=0$
$\left(16-7\right)\cdot\left(8+2\right)$
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