$\left(y+\frac{3}{4}\right)\left(y-\frac{3}{4}\right)$
$\left(2x^3y^5\:+\:4x^5z^4\right)$
$100+150+300-152-4$
$11-u-14u-13u$
$x\frac{dy}{dx}-cos3y=0$
$\frac{dy}{dx}=\frac{1+y^2}{1+x}$
$19+14+6+12+13$
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