$-4^3+\sqrt[3]{-125}-\left(-6^3\right)-\sqrt{225}$
$+8+4+9+5$
$5x+12=37$
$4x-8x+4x+4$
$-x^2+6x+1$
$\sqrt[3]{1+26}$
$\lim_{x\to\infty}\left(\frac{4x^3-2x^2+6}{\pi x^3+4}\right)$
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