$\frac{cos\:x\:tan\:x}{x}$
$4xy-8^2$
$\frac{16x^4-81y^4}{2x\:+3y\:}$
$\tan\left(x\right)+\cos\left(-x\right)+\tan\left(-x\right)=\cos\left(x\right)$
$\left(\frac{3}{4}\right)^{18}$
$\left(4x-x^3\right)^3$
$-8234+2583$
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