$\left(x^{-6}y^3z^2\right)^{-2}$
$\sqrt[3]{64x^{3}}$
$\lim_{n\to\infty}\left(e^{5+\frac{3}{n}}\right)$
$csc^2x-4=0$
$6x^3+5x^2-19x-10$
$2x+5<\:3x-1$
$64x^3-8$
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