$f\left(x\right)=\left(6x^2+7x\right)^2$
$\int\frac{x^2+x+2}{x^3-4x}dx$
$\frac{x^4}{4-x^2}$
$4x\:+\:9\:+\:12x\:-\:3$
$\frac { 1 } { 2 } = \frac { 1 } { p }$
$\lim_{x\to4}\frac{x^2+5x+4}{x+4}$
$\frac{1}{\csc\left(x-1\right)}-\frac{1}{\csc\left(x+1\right)}$
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