$\frac{\left(8x-4\right)}{x^2+2x}$
$\left\{-4\left[\left(-3\right)-2\right]5\right\}$
$\left(\:-10\::\:\left(\:17-12\right)\:+2\:\left(-8+5\right)\:-\:15\right)$
$x^2+x-20\le0$
$\left(-7x^8\right)\left(6x^3\right)$
$\int\ln5x^2\:dx$
$12+2\left(9-5\right)$
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