$\int\left(\frac{x}{\left(x^2-5\right)^4}\right)dx$

$\frac{1}{x\cdot x+1}$

$5x<3\left(x-4\right)+7$

$\left(3^2-3\right)-\left(2^2\cdot3^2\right)-\left(5^2\right)^0$

$\int\left(x-7\right)^2dx$

$f\left(x\right)\:=\:6x\frac{2}{3}\:\tan x$

$\left(2x^3+\frac{3}{4}\right)\left(2x^3-\frac{3}{4}\right)$