$s^2+7s-7s-49$
$\lim_{x\to\infty}\left(\frac{x^3+3x^2+2}{x^4+x^2+2}\right)$
$\lim_{x\to0}\left(\frac{6x^2-3x+2}{4x-1}\right)$
$x^2+6x+8\le\:\:0$
$16\frac{-1}{4}$
$\frac{d}{dx}\left(\frac{\left(2x^3+1\right)e^{x^8}}{x^2}\right)$
$-9-10+1$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!