$\int99xdx$
$\lim_{x\to0}\left(3x^2-6x+1\right)$
$\int\frac{4x^2}{\sqrt[3]{x^3+2}}dx$
$-1+-13+-3+2$
$3,194\:x\:2,333$
$9x^3-6x$
$\sqrt{004}$
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