$5\left(4x-1\right)$
$\int\frac{3x}{2e^{6x}}dx$
$\left(3x^3\right)\left(3^4\right)\left(-3x^2\right)$
$x^2+x+1<0$
$-12\:-\left(-2\right)$
$f\left(x\right)=\left(6x^3-10x^5\right)^4$
$\frac{6-\tan\left(x\right)}{6\csc\left(x\right)-\sec\left(x\right)}$
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