$x^2>3x-2$
$3^4\cdot10^4$
$\frac{4-x}{x}+6>14$
$\lim_{x\to0}\left(\frac{6-6\cos\left(x\right)}{sin\left(5x\right)}\right)$
$( 5 x ^ { \frac { 1 } { 8 } } ) ^ { 2 }$
$2^{x-15}+6=70$
$x^2-6x+9=25$
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