$\frac{dy}{dx}=\frac{x\sqrt{1-y^2}}{y\sqrt{x^2+1}}$
$6x+3x^2-4x$
$\cos\left(x\right)=-\frac{1}{\sqrt{3}}$
$\frac{1}{x}-\frac{1}{y}$
$36x^4-148x^2+16=0$
$\frac{2x^4+4x^2-16}{x-2}$
$\int\left(7x-3\right)\left(x-7\right)^2dx$
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