$\left(\left(2\right)\left(6\right)\left(9\right)\left(7\right)\left(\frac{2}{3}\right)\left(\frac{1}{2}\right)\right)$

$\frac{\sqrt{x+6}-3}{2-\sqrt[3]{2x+2}}$

$\lim_{x\to2}\left(x^2-7x+10\right)ln\left|x-2\right|$

$x^2-3x+18$

$2ax^2+3bx^3$

$4-x<x+10$

$\frac{2}{\left(x^3\right)}-\frac{10}{\sqrt[5]{x^2}}+2^5+x^2$