$x^2+20x=c$
$-9x^2-24x-16>0$
$t+0.2+-0.62t$
$-4+5\left\{1\left[11\left(-2+2\right)-10\right]\right\}+3$
$\lim_{x\to\infty}\left(\frac{x}{\log x}\right)$
$4-3\cdot2$
$\left(5x^2-4x\right)^2$
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